A ball collides impinges directly on a similar ball at rest. The first ball is brought to rest after the impact. If half of the kinetic energy is lost by impact, the value of coefficient of restitution (e) is

Question

Infinity Learn · Accepted Answer

∴ Initial $$KE$$, Ki $$=$$ $$12mu12+12mu22$$ $$=$$ $$12mu21and$$ final $$KE$$, Kf $$=$$ $$12mv21+12mv22$$ $$=$$ $$12mv22Loss$$ in $$KE$$, ∆K $$=$$ $$Ki-kf$$  $$=$$ $$12mu21-12mu22It$$ is given $$12(12mu21)$$ $$=$$ $$12mu21-12mv22($$∴ Half of its $$KE$$ is lost by $$impact)or$$ $$u21$$ $$=$$ $$2v22$$ or $$v2$$ $$=$$ $$u12Hence$$, coefficient of restitution, e $$=$$ |$$v2-v1u1-u2$$| $$=$$ $$v2u1$$ $$=$$ $$12$$

A ball collides impinges directly on a similar ball at rest. The first ball is brought to rest after the impact. If half of the kinetic energy is lost by impact, the value of coefficient of restitution (e) is

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