A ball of density ρ is gently released in a liquid of density o where ρ > o. What will be the acceleration of the free fall of the ball in the liquid ?
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a
g
b
(ρ−σ)g
c
(ρ−σ)g/ρ
d
ρg/(ρ−σ)
answer is C.
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Detailed Solution
Let Y be the volume of the ball.Weight of the ball = V pg∴ (Vρ)a=Vρg−Vσg=V(ρ−σ)g a=(ρ−σ)g/ρ