A ball of density ρ is gently released in a liquid of density o where ρ > o. What will be the acceleration of the free fall of the ball in the liquid ?

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(ρ−σ)g

(ρ−σ)g/ρ

ρg/(ρ−σ)

answer is C.

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Detailed Solution

Let Y be the volume of the ball.Weight of the ball = V pg∴ (Vρ)a=Vρg−Vσg=V(ρ−σ)g a=(ρ−σ)g/ρ

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