A ball does not pass through a copper ring at room temperature. The same ball, after heating, passes through the same ring. It shows due to heating, the ball
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a
expands
b
contracts
c
does not change
d
1 or 2
answer is B.
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Detailed Solution
Intially diameter of the ball was greater than that of the ring.When the ball passes through the ring , its diameter must be less than that of the ring.Therefore on heating the ball must contract.