First slide

Vertical projection from top of a tower

Question

A ball is dropped downwards to hit the ground at time t=0. After 1 second another ball is dropped downwards from the same point. The distance between them after 3 seconds is

Easy

A

25 m
B

20 m
C

50 m
D

9.8 m

Solution

Displacement for the first body $h_{1} = \frac{1}{2} g 3^{2}$
Displacement for the second body $h_{2} = \frac{1}{2} g 2^{2}$
Their separation $= \frac{1}{2} g (9 - 4) = 5 \times 5 = 25 m$

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