A ball is dropped from a height. Another ball is dropped from the same height after  4s. Their separation after 2 more seconds is ………..  m g=9.8 m/s2

First ball travelled for 6s and the second ball for 2s∴ Distance travelled by the first body is  s1=12gt12  =12×g×36=18g    Distance travelled by the second body is   s2=12gt22=12×g×4=2g   ∴ Their separation is 18g−2g =16g=16×9.8=156.80m