A ball falling freely from a height of 4.9 m ,hits a horizontal surface. If e = 3/4, then the ball will hit the surface second time after

Velocity on hitting the surface                          =2gh=2×9.8×4.9                           = 9.8 ms-1Velocity after first bounce, v = 34×9.8ms-1Time taken from first bounce to the second bounce = 2vg                       =2×34×9.8×19.8=1.5 s