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Q.

A ball falls freely from a height of 45 m. When the ball is at a height of 25 m, it explodes into two equalpieces. One of them moves horizontally with a speed of 10 ms-1. The distance between the two pieces on the ground is

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a

20 m

b

30 m

c

40 m

d

60 m

answer is A.

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Detailed Solution

Remaining time for the pieces to reach the ground, t=2×4510-2×2010=1 s x = 10×1=10 m∴ Distance between two pieces will be 20 m.

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