Q.
A ball falls freely from a height of 45 m. When the ball is at a height of 25 m, it explodes into two equalpieces. One of them moves horizontally with a speed of 10 ms-1. The distance between the two pieces on the ground is
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a
20 m
b
30 m
c
40 m
d
60 m
answer is A.
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Detailed Solution
Remaining time for the pieces to reach the ground, t=2×4510-2×2010=1 s x = 10×1=10 m∴ Distance between two pieces will be 20 m.