First slide

The steps in collision

Question

A ball falls freely from a height of 45 m. When the ball is at a height of 25 m, it explodes into two equal
pieces. One of them moves horizontally with a speed of $10 {ms}^{- 1}$ . The distance between the two pieces on the ground is

Moderate

A

20 m
B

30 m
C

40 m
D

60 m

Solution

Remaining time for the pieces to reach the ground,
$t = \sqrt{\frac{2 \times 45}{10}} - \sqrt{\frac{2 \times 20}{10}} = 1 s$
$x = 10 \times 1 = 10 m$
$∴$ Distance between two pieces will be 20 m.

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