Download the app

Questions  

A ball of 0.5 kg collided with wall at 30° with the normal at the point of contact with the wall and bounced back elastically. The speed of ball was 12ms-1. The contact remained for Is. What is the force applied by wall on ball? [JIPMER 2018]

a
123N
b
3N
c
63N
d
33N

detailed solution

Correct option is C

Given, m=0.5 kg, v = 12 ms-1, ∆t = 1s and θ=30°Force applied by wall on ball,             F=∆p∆t or F=pfH-piHΔt∵  In this elastic collision, final and initial velocities will be same but direction changes          (pf)H = mv cosθand    (pi)H = -mv cosθ∴          F=mvcosθ+mvcosθΔt=2mvcosθΔt                F=2×0.5×12×cos30°1=63 N

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.

Statement II : The equality of mg and R has no connection with the third law.


phone icon
whats app icon