Questions
A ball of 0.5 kg collided with wall at 30° with the normal at the point of contact with the wall and bounced back elastically. The speed of ball was . The contact remained for Is. What is the force applied by wall on ball? [JIPMER 2018]
detailed solution
Correct option is C
Given, m=0.5 kg, v = 12 ms-1, ∆t = 1s and θ=30°Force applied by wall on ball, F=∆p∆t or F=pfH-piHΔt∵ In this elastic collision, final and initial velocities will be same but direction changes (pf)H = mv cosθand (pi)H = -mv cosθ∴ F=mvcosθ+mvcosθΔt=2mvcosθΔt F=2×0.5×12×cos30°1=63 NTalk to our academic expert!
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