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Q.

A ball of mass 1 g and charge 10−8C  moves from a point A. where potential is 600 volt to the point B where potential is zero. Velocity of the ball at the point B is 20 cm/s. The velocity of the ball at the point A will be

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a

22.8 cm/s

b

228 cm/s

c

16.8 m/s

d

168 m/s

answer is A.

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Detailed Solution

By using 12m(v12−v22)=QV⇒12×10−3v12−(0.2)2=10−8(600−0)⇒v1=22.8cm/s
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