First slide

Second law

Question

A ball of mass 10 gm dropped from a height of 5m hits the floor and rebounds to a height of 1.25m. If the ball is in contact with the ground for 0.1s, the force exerted by the ground on the ball is (g=10 m/s²)

Moderate

A

0.5 N
B

1.5 N
C

0.15N
D

2.5 N

Solution

$F = \frac{dp}{dt} = \frac{m (v - u)}{t} where v = \sqrt{2 {gh}_{2}}, u = \sqrt{2 {gh}_{1}}$

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