Question

A ball of mass 2kg and another of mass 4kg are dropped together from a 60 feet tall building. After a fall of 30 feet each towards earth, their respective kinetic energies will be in the ratio of

Easy

Solution

Kinetic energy $= \frac{1}{2} {mv}^{2}$
As both balls are falling through same height therefore they possess same velocity.
but $KE \propto m$ (If v = constant)
$∴ \frac{{(KE)}_{1}}{{(KE)}_{2}} = \frac{m_{1}}{m_{2}} = \frac{2}{4} = \frac{1}{2}$

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