A ball of mass 5kg hangs from a spring of force constant k N/m and oscillates with certain time period. If the ball is removed, the spring shortens by

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(2g) m

(g) m

answer is B.

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Detailed Solution

When the ball is in equilibrium Mg = kxs where xs = static deflection of the spring. Shortening of spring = xs = Mg/K =

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