First slide

Simple hormonic motion

Question

A ball of mass 5kg hangs from a spring of force constant k N/m and oscillates with certain time period. If the ball is removed, the spring shortens by

Easy

A

$\large \left( {\frac{K}{g}} \right)m$
B

$\large \left( {\frac{{5g}}{K}} \right)m$
C

(2g) m
D

(g) m

Solution

When the ball is in equilibrium Mg = kx_s where x_s = static deflection of the spring.
$\large \therefore$ Shortening of spring = x_s = Mg/K = $\large \frac{{5g}}{K}$

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