Questions
A ball of mass m falls vertically to the ground from a height h1 and rebound to a height h2. The change in momentum of the ball on striking the ground is
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Correct option is B
When ball falls vertically downward from height h1 its velocity v→1=2gh1and its velocity after collision v→2=2gh2Change in momentumΔP→=m(v→2−v→1)=m(2gh1+2gh2)(because v→1 and v→2 are opposite in direction)
Similar Questions
A ball is projected vertically down with an initial velocity from a height of 20 m onto a horizontal floor. During the impact it loses 50% of its energy and rebounds to the same height. The initial velocity of its projection is (in m/s) [Take g = 10 m/s2]
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