Q.
A ball of mass m falls vertically to the ground from a height h1 and rebound to a height h2. The change in momentum of the ball on striking the ground is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
mg(h1−h2)
b
m(2gh1+2gh2)
c
m2g(h1+h2)
d
m2g(h1+h2)
answer is B.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
When ball falls vertically downward from height h1 its velocity v→1=2gh1and its velocity after collision v→2=2gh2Change in momentumΔP→=m(v→2−v→1)=m(2gh1+2gh2)(because v→1 and v→2 are opposite in direction)
Watch 3-min video & get full concept clarity