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Questions  

A ball of mass m falls vertically to the ground from a height h1 and rebound to a height h2. The change in momentum of the ball on striking the ground is

a
mg(h1-h2)
b
m(2gh1+2gh2)
c
m2g(h1+h2)
d
m2g(h1+h2)

detailed solution

Correct option is B

When ball falls vertically downward from height h1 its velocity v2→ = 2gh2Change in momentum∆P→ = m(v2→-v1→) = m(2gh1+2gh2)(because v1→ and v2→ are opposite in direction)

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Similar Questions

Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.

Statement II : The equality of mg and R has no connection with the third law.


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