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An Intiative by Sri Chaitanya
a
vsin2θ+e2cos2θ ,tan-1tanθe
b
2vsin2θ+e2cos2θ ,tan-1tanθe
c
2vsin2θ+e2cos2θ ,tan-1tanθ2e
d
vsin2θ+e2cos2θ , tan-1tanθ2e
answer is A.
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