Q.

A ball of mass m is projected from the ground with an initial velocity u making an angle of θ with thevertical. What is the change in velocity between the point of projection and the highest point?

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a

u cos θ  downward

b

u cos θ upward

c

u sin θ upward

d

u sin θ downward

answer is A.

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Detailed Solution

Δv=aΔt=a·T2=(-gj^)ucosθg=(-ucosθ)j^Therefore, change in velocity is u cos θ in downward direction.
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A ball of mass m is projected from the ground with an initial velocity u making an angle of θ with thevertical. What is the change in velocity between the point of projection and the highest point?