Q.
A ball of mass m is projected from the ground with an initial velocity u making an angle of θ with thevertical. What is the change in velocity between the point of projection and the highest point?
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a
u cos θ downward
b
u cos θ upward
c
u sin θ upward
d
u sin θ downward
answer is A.
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Detailed Solution
Δv=aΔt=a·T2=(-gj^)ucosθg=(-ucosθ)j^Therefore, change in velocity is u cos θ in downward direction.
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