A ball of mass m is projected from the ground with an initial velocity u making an angle of θ with thevertical. What is the change in velocity between the point of projection and the highest point?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
u cos θ downward
b
u cos θ upward
c
u sin θ upward
d
u sin θ downward
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Δv=aΔt=a·T2=(-gj^)ucosθg=(-ucosθ)j^Therefore, change in velocity is u cos θ in downward direction.
A ball of mass m is projected from the ground with an initial velocity u making an angle of θ with thevertical. What is the change in velocity between the point of projection and the highest point?