Questions
A ball of mass m and radius r is rolling without slipping inside a hemispherical shell of radius R. It is released from rest from point A as shown in figure. The angular velocity of centre of the ball in position B about the centre of the shell is
detailed solution
Correct option is B
K.E. of ball in position B = mg(R-r)Here m = mass of ball.Since it rolls without slipping the ratio of rotational to translational kinetic energy will be 25.KRKT = 25KT = 57mg(R-r)12mv2 = 57mg(R-r)v =10 g(R-r)7ω = vR-r = 10 g7(R-r)Talk to our academic expert!
Similar Questions
I. Speed of any point on rigid body executing rolling motion can be calculated by the expression
where r is the distance of point from instantaneous centre of rotation.
II. Rolling motion of rigid body can be considered as a pure rotation about instantaneous centre of rotation.
Which of the above statement{s} is/are correct?
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