A ball of mass m is released from A inside a smooth wedge of mass m as shown in fig. What is the speed of the wedge when the ball reaches point B?
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a
gR3212
b
2gR
c
5gR2312
d
32gR
answer is A.
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Detailed Solution
Loss of PE=Gain in KEmgR cosθ=12mv2+12mv1 cosθ-v2+12mv1 sinθ2---1 From conservation of linear momentum mv1 cos45o-v=mv-------(2) Here v1 is the velocity of ball w.r.t wedge solve to get speed of wedge (v)