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Questions  

A ball of mass m is released from the top of an inclined plane of inclination θ as shown in figure. It strikes a rigid surface at a distances 3h4from top elastically. Impulse imparted to ball by the rigid
surface is

a
m32gh
b
m3gh
c
2m3gh
d
m6gh

detailed solution

Correct option is D

Loss in PE = Gain in KE                     mgh1=12mv2              mg×34h=12mv2⇒v=3gh2Now, impulse imparted,  J=2mv=2m3gh2=m6gh

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