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Q.

A ball of mass m is released from the top of an inclined plane of inclination θ as shown in figure. It strikes a rigid surface at a distances 3h4from top elastically. Impulse imparted to ball by the rigidsurface is

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a

m32gh

b

m3gh

c

2m3gh

d

m6gh

answer is D.

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Detailed Solution

Loss in PE = Gain in KE                     mgh1=12mv2              mg×34h=12mv2⇒v=3gh2Now, impulse imparted,  J=2mv=2m3gh2=m6gh
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