A ball of mass m is thrown upward with a velocity v. If air exerts an average resisting force F, the velocity with which the ball returns back to the thrower is
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a
Vmgmg+F
b
VFmg+F
c
Vmg−Fmg+F
d
Vmg+Fmg
answer is C.
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Detailed Solution
For upward motion, Retarding force = m g + F∴ Retardation a=mg+FmDistance s=V22a=V2m2(mg+F)For downward motion, force = m g - F∴ Acceleration a′=mg−FmDistance s′=v′22a′=v′2m2(mg−F)Since s′=s, v′2mg−F=v2mg+F∴ v′=vmg−Fmg+F