Questions
A ball of mass m is thrown vertically up in air from the ground with initial speed u and is found to return to the starting point with a lesser speed of v. If g is the acceleration due to gravity, the maximum height reached by the ball is
detailed solution
Correct option is D
energy loss by the ball =12m(u2-v2)=2mgh h is the height loss due resistive force h=u2-v24g so height it has reached u22g-h=u22g-(u2-v24g)=u2+v24gTalk to our academic expert!
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In the figure given the position-time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 s is :
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