First slide

Projection Under uniform Acceleration

Question

A ball of mass M is thrown vertically upwards. Another ball of mass2M is thrown at an angle $θ$ to vertical. Both of them stay in air for the same period of time. The heights attained by the two are in the ratio:

Easy

A

1:2
B

2:1
C

1:1
D

1:cos $θ$

Solution

$H_{\max} = \frac{u^{2} \sin^{2} θ}{2 g} = \frac{g}{g} {(\frac{2 usinθ}{g})}^{2} = \frac{{gT}^{2}}{g}$

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