A ball of mass is thrown in air with speed v1 from height h1 to a height h2>h1 . Find the work done by the balls by the air resistance
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a
mg(h2−h1)
b
12m(v22−v12)
c
mg(h2−h1)+12m(v2 2−v1 2)
d
mg(h2+h1)−12m(v2 2-v1 2)
answer is C.
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Detailed Solution
Given mass of ball = m Let speed = vWork done by gravity Wg=-mg(h2−h1) According to work-energy theoremwg+wair=ΔKE wg+wair=12m(v22−v12) wair=mg(h2−h1)+12m(v22−v12)