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A ball A moving with momentum 2i^+6j^ collides with another identical moving ball B with momentum −4j^ and momentum of ball B after collision is 2j^ . The coefficient of restitution in the collision is x15 . Find the value of x.

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Detailed Solution

Since the momentum exchange in j^ - direction ⇒ line of impulse is inj^ -direction (2i^+6j^)−4j^=PA→+2j^⇒PA→=2i^ ∴e=2m−06m+4m=210=15

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A ball A moving with momentum 2i^+6j^ collides with another identical moving ball B with momentum −4j^ and momentum of ball B after collision is 2j^ . The coefficient of restitution in the collision is x15 . Find the value of x.