A ball moving with speed v hits another identical ball at rest. The two balls stick together after collision. If specific heat of the material of the balls is S, the temperature rise resulting from the collision is
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a
v28S
b
v24S
c
v22S
d
v2S
answer is A.
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Detailed Solution
Initial momentum = mvFinal momentum = 2mVBy the conservation of momentum, mv=2mV⇒V=v2K.E. of the system after the collision = 122m v22∴ loss in K.E. =12mv2−14mv2=14mv2This loss in K.E. will increase the temperature ∴2m×s×Δt=14mv2⇒Δt=v28s