A ball is projected in a direction inclined to the vertical and bounces on a smooth horizontal plane. The range of one rebound is R. If the coefficient of restitution is e, then range of the next rebound is
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a
R'=eR
b
R'=e2R
c
R'=Re
d
R'=R
answer is A.
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Detailed Solution
R=2u cos θ⋅u sin θgAfter impact horizontal component remains the same =u cos θThe vertical component becomesV=e(u sin θ)New range R′=2u cos θ⋅eu sin θgR'=eR