First slide
Projection Under uniform Acceleration

A ball is projected from the ground at angle θ with the horizontal. After 1s it is moving at angle 45° with the horizontal and after 2 s it is moving horizontally. What is the velocity of projection of the ball?


After one second it is moving 450 with horizontal 

tan450=usinθ-g×1ucosθ=1 ucosθ=usinθ-g1 after two seconds it moves horizontally means it is at the higest point  usinθg=2 usinθ=2g substituting in 1 ucosθ=g u=usinθ2+ucosθ2 u=2g2+g2=5g=105

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