A ball is projected from the ground at angle θ with the horizontal. After $$1s$$ it is moving at angle $$45$$° with the horizontal and after $$2$$ s it is moving horizontally. What is the velocity of projection of the ball?

Question

A ball is projected from the ground at angle θ with the horizontal. After $$1s$$ it is moving at angle $$45$$° with the horizontal and after $$2$$ s it is moving horizontally. What is the velocity of projection of the ball?

Infinity Learn · Accepted Answer

After one second it is moving $$450$$ with horizontal $$tan450=usin$$θ$$-g$$×$$1ucos$$θ$$=1$$ ucosθ$$=usin$$θ$$-g$$⇒⇒$$1$$ after two seconds it moves horizontally means it is at the higest point  usinθ$$g=2$$ usinθ$$=2g$$ substituting in $$1$$ ucosθ$$=g$$ $$u=usin$$θ$$2+ucos$$θ$$2$$ $$u=2g2+g2=5g=105$$

A ball is projected from the ground at angle $θ$ with the horizontal. After 1s it is moving at angle 45° with the horizontal and after 2 s it is moving horizontally. What is the velocity of projection of the ball?

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A ball is projected from the ground at angle θ with the horizontal. After 1s it is moving at angle 45° with the horizontal and after 2 s it is moving horizontally. What is the velocity of projection of the ball?

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A ball is projected from the ground at angle $θ$ with the horizontal. After 1s it is moving at angle 45° with the horizontal and after 2 s it is moving horizontally. What is the velocity of projection of the ball?