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Q.

A ball is projected from ground with a speed of 20 ms-1at an angle of 450 with horizontal. There is a wall of 25 m height at a distance of 10m from the projection point. The ball will hit the wall at a height of

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a

5m

b

7.5 m

c

10m

d

12.5 m

answer is B.

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Detailed Solution

Since,  usinθ×t=10 m⇒  20sin45°t=10⇒                  t=1020sin45°=12 s Now, y=20sin45°t-12gt2=20×12×12-12×10×12=7.5 m
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A ball is projected from ground with a speed of 20 ms-1at an angle of 450 with horizontal. There is a wall of 25 m height at a distance of 10m from the projection point. The ball will hit the wall at a height of