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A ball is projected from ground with a speed of 20 ms-1at an angle of 450 with horizontal. There is a wall of 25 m height at a distance of 10m from the projection point. The ball will hit the wall at a height of 

a
5m
b
7.5 m
c
10m
d
12.5 m

detailed solution

Correct option is B

Since,  usinθ×t=10 m⇒  20sin45°t=10⇒                  t=1020sin45°=12 s Now, y=20sin45°t-12gt2=20×12×12-12×10×12=7.5 m

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