A ball is projected from the ground with speed 10 ms-1 at an angle 450 with horizontal. It collides with wall at a distance '4m' from the point of projection and returns to its original position. The coefficient of restitution between ball and wall is
Since the wall is smooth, vertical component of velocity of the ball after the impact remains unchanged and horizontal component of velocity after the impact becomes (e x 10 cos450) m/s.
Now , tOAP + tPBO = T