A ball 'A' is projected from origin with an initial velocity v0= 700cm/sec in a direction 370 above the horizontal as shown in fig .Another ball 'B' 300 cm from origin on a line 370 above the horizontal is released from rest at the instant A starts. How far will B have fallen when it is hit by A?

)BAC is vertical straight line from figure from △BOC ,  sin37=BCOB BC=OB sin37=300×35=180cm let both balls collide after time t second AC=vertical height of projectile=uyt-12gt2 AC=(700 sin37)t-gt22 AC=(700×35 )t-gt22 AC=420t-gt22---(1) BA=y=ut+12gt2 BA=0+gt22---(2) BA+AC=BC=180cm substitute equtions (1)&(2) gt22+420t-gt22=180 t=180420=37 BA=gt22=9802×372=90cm