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Q.

Ball A is projected from tower of height 30 m and B is projected horizontally at 6 m/s from tower of height 60 m. If A and B collide in air, then find the separation d between the towers in meters.

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answer is 30.

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Detailed Solution

30sin⁡53∘t−12gt2+12gt2=30⇒ 30×45t=30⇒ t=54s d=30cos⁡53∘t+6t⇒ d=24t=2454=30m

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