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Q.

A ball is projected horizontally from a height of 100 m from the ground with a speed of 20 ms-1. Taking g=10 ms-2 and based on the information provided, answer the following questions.The time taken to reach the ground isThe horizontal distance it covers before striking the ground isThe angle with the vertical which it strikes the ground is

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a

5s

b

25s

c

35s

d

45s

e

205m

f

405m

g

605m

h

805m

i

tan−1⁡13

j

tan−1⁡5

k

tan−1⁡15

l

tan−1⁡17

answer is , , .

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Detailed Solution

100=12gt2                     ∵y=12gt2⇒t=20010=20=25sx=ut=20(25)⇒ x=405mtan⁡θ=vxvySince vx=u and vy=gt⇒ tan⁡θ=ugt=20(10)(25)⇒ tan⁡θ=15⇒ θ=tan−1⁡15
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