First slide

Projection Under uniform Acceleration

Question

A ball is projected horizontally from the top of a building 19.6 m high. If the line joining the point of projection to the point where it hits the ground makes an angle of 45° to the horizontal, the initial velocity of the ball is

Moderate

A

4.9 ms^-1
B

9.8 ms^-1
C

19.6 ms^-1
D

14.7 ms^-1

Solution

Here $H = R = U \sqrt{\frac{2 H}{g}}$
$\begin{array}{l} H^{2} = U^{2} \frac{2 H}{g} \\ U = \sqrt{\frac{gH}{2}} = 9 .8 m / s \end{array}$

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