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Projection Under uniform Acceleration

Question

A ball is projected horizontally from the top of a building 19.6 m high. If the line joining the point of projection to the point where it hits the ground makes an angle of 45° to the horizontal, the initial velocity of the ball is

Moderate
Solution


R = u\sqrt {\frac{{2h}}{g}} \Rightarrow 19.6 = u\sqrt {\frac{{2 \times 19.6}}{{9.8}}} \Rightarrow u = 9.8m{s^{ - 1}}



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