Q.
A ball is projected horizontally with a speed V from the top of a plane inclined at angle 450 with the horizontal. How far from the point of projection will the ball strike the plane?
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a
V2g
b
2V2g
c
2V2g
d
22V2g
answer is D.
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Detailed Solution
down the plane Range =R=u2gcos2β[sin(2α+β)+sinβ]here α=0=angle of projection is along horizontal line;substituteR=u2gcos245∘sin45∘+sin45∘R=u2g12×2×12R=22V2g [ Here u=v]
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