A ball is projected horizontally with a speed v from the top of plane inclined at an angle 450 with the horizontal. How far from the point of projection will the ball strike the plane?

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2v2g

2[2v2g]

v2g

2v2g

answer is B.

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Detailed Solution

x = vt or y = 12gt2tan 450 = yxor y = xor y = gx22v2 or x = gx22v2 or x = 2v2gAlso, y = 2v2g or l2 = x2+y2l = 2×xor l = 2[2v2g]

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