Question

A ball is projected horizontally with a velocity of 5 m/s from the top of a building 19.6 m high. How long will the ball take to hit the ground ?

Moderate

Solution

Let t s be time taken by the ball to hit the ground.
$∵ H = \frac{1}{2} {gt}^{2} ∴ t = \sqrt{\frac{2 H}{s}} = \sqrt{\frac{2 \times 19 .6 m}{9 .8 {ms}^{- 2}}} = 2 s$

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