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Q.

A ball is projected upwards from the top of a tower with a velocity of 50ms−1making an angle of 30° with the horizontal. The height of the tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground ?

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a

2 s

b

5 s

c

7 s

d

9 s

answer is C.

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Detailed Solution

The vertically upward component of the velocity of projection =50sin⁡30∘m/s=25ms−1If t is the time taken to reach the ground, we have s=−u0t+12gt2or 70=−25t+1210t2or 5t2−25t−70=0 so t=−2s or t=−7sHere, t = -2s is not valid

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A ball is projected upwards from the top of a tower with a velocity of 50ms−1making an angle of 30° with the horizontal. The height of the tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground ?