A ball is projected upwards from the top of a tower with a velocity of $$50ms$$−$$1making$$ an angle of $$30$$° with the horizontal. The height of the tower is $$70$$ m. After how many seconds from the instant of throwing will the ball reach the ground ?

Question

A ball is projected upwards from the top of a tower with a velocity of $$50ms$$−$$1making$$ an angle of $$30$$° with the horizontal. The height of the tower is $$70$$ m. After how many seconds from the instant of throwing will the ball reach the ground ?

Infinity Learn · Accepted Answer

The vertically upward component of the velocity of projection $$=50sin$$⁡$$30$$∘$$m/s=25ms$$−$$1If$$ t is the time taken to reach the ground, we have  $$s=$$−$$u0t+12gt2or$$ $$70=$$−$$25t+1210t2or$$ $$5t2$$−$$25t$$−$$70=0$$ so $$t=$$−$$2s$$ or $$t=$$−$$7sHere$$, t $$=$$ $$-2s$$ is not valid

A ball is projected upwards from the top of a tower with a velocity of $50 {ms}^{- 1}$ making an angle of 30° with the horizontal. The height of the tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground ?

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A ball is projected upwards from the top of a tower with a velocity of 50ms−1making an angle of 30° with the horizontal. The height of the tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground ?

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A ball is projected upwards from the top of a tower with a velocity of $50 {ms}^{- 1}$ making an angle of 30° with the horizontal. The height of the tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground ?