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A ball is projected upwards from the top of the tower with a velocity 50 m/ sec. making angle 30° with the horizontal.The height of the tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground.

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Detailed Solution

Sy=uyt+12ayt2⇒−70=50sin30t−12×(10)t2⇒−70=25t−5t2⇒5t2−25t−70=0⇒t2−5t−14=0⇒t2−7t+2t−14=0⇒t=7sec

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