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A ball is projected vertically down with an initial velocity from a height of 20 m onto a horizontal floor. During the impact it loses 50% of its energy and rebounds to the same height. The initial velocity of its projection is (in m/s)  [Take g = 10 m/s2]


Let ball is projected vertically downward with velocity v from height h
Total energy at point  A=12mv2+mgh

During collision loss of energy is 50% and the ball rises up to same height. It means it possess only potential energy at same level.

50% 12mv2+mgh=mgh




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