Download the app

Collisions

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
Question

A ball is projected vertically down with an initial velocity from a height of 20 m onto a horizontal floor. During the impact it loses 50% of its energy and rebounds to the same height. The initial velocity of its projection is (in m/s)  [Take g = 10 m/s2]

Easy
Solution

Let ball is projected vertically downward with velocity v from height h
Total energy at point  A=12mv2+mgh

During collision loss of energy is 50% and the ball rises up to same height. It means it possess only potential energy at same level.

50% 12mv2+mgh=mgh

1212mv2+mgh=mgh

v=2gh=2×10×20

v=20m/s


Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


ctaimg

Create Your Own Test
Your Topic, Your Difficulty, Your Pace


Similar Questions

A body of mass 5 kg moving with a velocity 10 m/s collides with another body of the mass 20 kg at rest and comes to rest. The velocity of the second body due to collision is


phone icon
whats app icon