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A ball is projected with a velocity $20 m s^{- 1}$ at an angle of $30^{0}$ with the horizontal from the top of a tower of height 40 m, the ratio of the time taken by the ball to reach to the same height and that taken to hit the ground is

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detailed solution

Correct option is A

Time taken to come back to the same height is t1=2u sin θg=2×20×1210=2 s. If t2 is the time taken to hit the ground t2=4 s. Now t1t2=24=12 .

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A ball is projected with a velocity 20 ms−1 at an angle of 300 with the horizontal from the top of a tower of height 40 m, the ratio of the time taken by the ball to reach to the same height and that taken to hit the ground is

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Ready to Test Your Skills?

free study material

A ball is projected with a velocity $20 m s^{- 1}$ at an angle of $30^{0}$ with the horizontal from the top of a tower of height 40 m, the ratio of the time taken by the ball to reach to the same height and that taken to hit the ground is