A ball of radius r rolls inside a hemispherical shell of radius R. It is released from rest from point A as shown in figure and the ball starts rolling without slipping. The angular velocity of centre of the ball in position B about the centre of the shell is:
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a
b
10g7(R-r)
c
d
answer is B.
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Detailed Solution
Loss in P.E. = Gain in K.E.mgR-r=12mv2(1+K2r2) and v=(R-r)ω For a solid sphere K2=2r25 ⇒v=10g(R-r)7 ω=vR-r=10g7(R-r)