First slide

Release from certain height

Question

A ball is released from the top of height h meter. It takes T second to reach the ground. Where is the ball at the time T/2 sec?

Easy

A

At (h/4) m from the ground.
B

At (h/2) m from the ground.
C

At (3h/4) m from the ground.
D

Depends upon the mass and volume of the ball.

Solution

$h = \frac{1}{2} {gT}^{2}, h' = 0 + \frac{1}{2} g {(\frac{T}{2})}^{2} = \frac{h}{4}$
= At $\frac{3 h}{4}$ from the ground.

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