First slide

Rectilinear Motion

Question

A ball is released from the top of a tower of height h. It takes time T to reach the ground. What is the position of the ball (from ground) after time T/3?

Moderate

A

$h / 9 m$
B

$7 h / 9 m$
C

$8 h / 9 m$
D

$17 h / 18 m$

Solution

$We have h = \frac{1}{2} g T^{2}$
$In T / 3 second, distance fallen = \frac{1}{2} g {(\frac{T}{3})}^{2} = \frac{h}{9}$
$S o p o s i t i o n o f t h e b a l l f r o m t h e g r o u n d i s$
$h - \frac{h}{9} = \frac{8 h}{9} m$

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