First slide

Release from certain height

Question

A ball is released from the top of a tower of height h m. It takes T s to reach the ground. What is the position of the ball in $\frac{T}{3} s$ ?

Moderate

A

$\frac{h}{9} m$ from the ground
B

$\frac{7 h}{9} m$ from the ground
C

$\frac{8 h}{9} m$ from the ground
D

$\frac{17 h}{9} m$ from the ground

Solution

$T = \sqrt{\frac{2 h}{g}} y_{t = \frac{T}{3}} = h - \frac{1}{2} g {(\frac{1}{3} \sqrt{\frac{2 h}{g}})}^{2} = \frac{8 h}{9} m$

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