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Q.

A ball is released from the top of a tower of height h metre. It takes T  sec to reach the ground. What is the position of the ball in T/3  sec?

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a

h9  metre from the ground

b

7h/9  metre from the ground

c

8h/9  metre from the ground

d

17h/18  metre from the ground

answer is C.

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Detailed Solution

We have h=12gT2 In T3  sec, the distance fallen=12g(T3)2=h9 ∴  Position of the ball from the ground=h−h9=8h9m
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