A ball is released from the top of a tower of height h metre. It takes T sec to reach the ground. What is the position of the ball in T/3 sec?

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h9 metre from the ground

7h/9 metre from the ground

8h/9 metre from the ground

17h/18 metre from the ground

answer is C.

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Detailed Solution

We have h=12gT2 In T3 sec, the distance fallen=12g(T3)2=h9 ∴ Position of the ball from the ground=h−h9=8h9m

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