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Q.

A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

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a

1 : 2 : 3

b

1 : 4 : 9

c

1 : 3 : 5

d

1 : 5 : 3

answer is C.

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Detailed Solution

When the ball is released from the top of tower then ratio of distances covered by the ball in first, second and third secondhI:hII:hIII=1:3:5:  [because  hn∝(2n−1)]∴ Ratio of work done  mghI:mghII:mghIII= 1:3:5
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