A ball is rising towards the surface with a constant velocity in a liquid whose density is four times that of the material of the ball. How many times of its weight is the drag force acting on the rising ball
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a
2
b
3
c
4
d
5
answer is B.
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Detailed Solution
Let ρ be the density of the material of the ball, the equation of motion is given by 43πr3ρg−43πr3.4ρg+F=0 ; F = force of friction & r = radius of the ball∴F=43πr3.3ρg = 3 times the weight of the ball