A ball rolls off top of a stair way with a horizontal velocity ms-1. If the steps are h metres high and b metres wide, the ball will just hit the edge of nth step, if n equals to
If the ball hits the nth step, the horizontal and vertical distances traversed are nb and nh, respectively. Let t be the time taken by the ball for these horizontal and vertical displacement. Then, velocity along horizontal direction remains constant = u, initial vertical velocity is zero.
nb = ut … (i)
nh = 0 + (l/2) gt2 …(ii)
From Eqs. (i) and (ii), we get by eliminating t.