First slide
Rolling motion
Question

A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of 
mass is K. If radius of the ball be R, then the fraction of total energy associated with its rotational energy
will be

Moderate
Solution

Moment of inertia,  I=mK2

  Ball is rolling without slipping, v=Rω

Translational kinetic energy,  KR=12Iω2=mK2v22R2

   Total kinetic energy  =12mv2+mK2v22R2

Required fraction  =mK2v22R212mv2+mK2v22R2=K2R2+K2

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