Questions
A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of
mass is K. If radius of the ball be R, then the fraction of total energy associated with its rotational energy
will be
detailed solution
Correct option is A
Moment of inertia, I=mK2∵ Ball is rolling without slipping, v=RωTranslational kinetic energy, KR=12Iω2=mK2v22R2∴ Total kinetic energy =12mv2+mK2v22R2Required fraction =mK2v22R212mv2+mK2v22R2=K2R2+K2Talk to our academic expert!
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